India 92 for 4 (Rohit 46*, Zampa 3-16) beat Australia 90 for 5 (Wade 43*, Finch 31, Axar 2-13) by six wickets
Rohit Sharma smashed four fours and as many sixes in his unbeaten 20-ball 46 to help India overhaul Australia’s 90 for 5 in an eight-over contest in Nagpur. The win meant the series is now levelled 1-1 with the final T20I to be played in Hyderabad on Sunday.
A wet patch in the outfield, thanks to Thursday’s rain, delayed the start of the match by two and half hours. Even when the umpires decided to go ahead, they did so by saying “although the conditions are not perfect, they are safe to play”.
India, bolstered by the return of Jasprit Bumrah, put Australia in after winning the toss. With each bowler allowed up to two overs, they didn’t need a sixth bowling option. So they decided to strengthen their batting, bringing in Rishabh Pant for Bhuvneshwar Kumar.
Aaron Finch‘s 15-ball 31 and Matthew Wade‘s unbeaten 20-ball 43 helped the visitors put up a competitive total despite Axar Patel conceding only 13 from his two overs. India, however, had the advantage of knowing the target. While Adam Zampa threatened to derail their chase with three quick wickets, Rohit stayed calm to see his side through.
More to follow
This article was originally published by Espncricinfo.com. Read the original article here.